3x-2=x^2-4

Solution for 3x-2=x^2-4 equation:

3x-2=x^2-4

We move all terms to the left:

3x-2-(x^2-4)=0

We get rid of parentheses

-x^2+3x+4-2=0

We add all the numbers together, and all the variables

-1x^2+3x+2=0

a = -1; b = 3; c = +2;
Δ = b2-4ac
Δ = 32-4·(-1)·2
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{17}}{2*-1}=\frac{-3-\sqrt{17}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{17}}{2*-1}=\frac{-3+\sqrt{17}}{-2}
$